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2x^2-90=-8x
We move all terms to the left:
2x^2-90-(-8x)=0
We get rid of parentheses
2x^2+8x-90=0
a = 2; b = 8; c = -90;
Δ = b2-4ac
Δ = 82-4·2·(-90)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-28}{2*2}=\frac{-36}{4} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+28}{2*2}=\frac{20}{4} =5 $
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